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5x^2/3=32
We move all terms to the left:
5x^2/3-(32)=0
We multiply all the terms by the denominator
5x^2-32*3=0
We add all the numbers together, and all the variables
5x^2-96=0
a = 5; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·5·(-96)
Δ = 1920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1920}=\sqrt{64*30}=\sqrt{64}*\sqrt{30}=8\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{30}}{2*5}=\frac{0-8\sqrt{30}}{10} =-\frac{8\sqrt{30}}{10} =-\frac{4\sqrt{30}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{30}}{2*5}=\frac{0+8\sqrt{30}}{10} =\frac{8\sqrt{30}}{10} =\frac{4\sqrt{30}}{5} $
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